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1) calculate the magnetomotive force (in amperre-turns) of thefollowing sources:

ID: 1830412 • Letter: 1

Question

1) calculate the magnetomotive force (in amperre-turns) of thefollowing sources: a) 500-turn coil with an electron flow of 24 mA. b) current of 1.5 amperes flowing through a 75-turncoil. 2)Define the terms normally-open and normally-clpsed contactas they apply to a relay. 1) calculate the magnetomotive force (in amperre-turns) of thefollowing sources: a) 500-turn coil with an electron flow of 24 mA. b) current of 1.5 amperes flowing through a 75-turncoil. 2)Define the terms normally-open and normally-clpsed contactas they apply to a relay.

Explanation / Answer

1) Magnetomotive force is given by     Fm = NI a) N = 500, I = 24mA     Fm = (500)(0.024)     Fm = 12 ampere turns b) N = 75, I = 1.5A     Fm = (75)(1.5)     Fm = 112.5 ampereturns 2) Relay is an electromagnetic switch. Its on and offoperation is controlled by electric current. Normally closed means that when the coil in the relay isnot energized, the relay switch is closed completing thecircuit. When coil is energized, then the switch opens and thecircuit is broken. Normally open means that when the coil in the relay is notenergized, the relay switch is open and the circuit isimcomplete. When coil is energized, then the switch closes andthe circuit is complete. b) N = 75, I = 1.5A     Fm = (75)(1.5)     Fm = 112.5 ampereturns 2) Relay is an electromagnetic switch. Its on and offoperation is controlled by electric current. Normally closed means that when the coil in the relay isnot energized, the relay switch is closed completing thecircuit. When coil is energized, then the switch opens and thecircuit is broken. Normally open means that when the coil in the relay is notenergized, the relay switch is open and the circuit isimcomplete. When coil is energized, then the switch closes andthe circuit is complete.