An n-channel enhancement mode MOSFET has parameters Vtr=2V andK=0.4mA/V^2 a)if V

Question

An n-channel enhancement mode MOSFET has parameters Vtr=2V andK=0.4mA/V^2 a)if Vgs=4.3V how large must Vds be for constantcurrent-region operation? b)what value of id(current) flows for this Vgs? c)what value of id flows if Vds is reduced to 2V? An n-channel enhancement mode MOSFET has parameters Vtr=2V andK=0.4mA/V^2 a)if Vgs=4.3V how large must Vds be for constantcurrent-region operation? b)what value of id(current) flows for this Vgs? c)what value of id flows if Vds is reduced to 2V?

Explanation / Answer

Given Vtn = 2V , K = 0.4 mA / V2 (a) Vgs = 4.3 V For constant current -region operation Vds > Vgs -Vtn                                                     => Vds > 4.3 V - 2V                                                    => Vds > 2.3 V (b)   Current in saturation region,                I = (1/2) K ( Vgs - Vth)2 = (1/2)(0.4mA)(4.3-2)2 =>         I = 1.058 mA (c) If Vds = 2 V => Device is in linear region Current   I = K { (Vgs-Vth)Vds - Vds2/2}              => I = (0.4mA) { (4.3-2)(2) - 2*2/2 }              => I = (0.4mA) { 4.6 - 2}              => I = 1.040mA I hope this helps you

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