In part C of this question, theKVL equation used to solve the question: was give

Question

In part C of this question, theKVL equation used to solve the question: was given as follows (retrievedfrom a previous post):


Can someone explain how thecorrect answer is based off the former equation and not the latter(or if the former equation is even correct at all)?

Explanation / Answer

You are correct and the latter answer is right. Because thereference current is leaving the dotted terminal on the right, thanthe induced voltage on the other side is negative at the dottedterminal such that from KVL, V1 - Mdi2/dt - Ldig/dt =0    =>   V1=Mdi2/dt + Ldig/dt The rule is, if the reference current enters the dotted terminal,then the induced voltage on the other side is positive at the otherdot, and if the reference current leaves the dotted terminal, thenthe induced voltage is negative at the other dot. I hope this helps.

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