We want to store sufficient energy in a 0.01 F capacitor to supply5 horsepower (
ID: 1829606 • Letter: W
Question
We want to store sufficient energy in a 0.01 F capacitor to supply5 horsepower (hp) for 1 hour. To what voltage must the capacitor becharged? (One horsepower is equivalent to 745.7 watts.) Does thisseem to be a practical method for storing this amount of energy? Doyou think that an electric automobile design based on capacitiveenergy storage is feasible?Explanation / Answer
(a) Energy Stored in aCapacitor E = (1/2) CV2 where , C = capacitance , V = voltageapplied to capacitor Energy required in above problem , E =745.5*(60*60) J (Since 1 hour = 3600seconds) Hence V = (2E/C) = (2*745.5*60*60/0.01) V => V = 23168.1 V (b) As seen , the requiredvoltage is nearly 23000 V which is practically infeasible , eventhough such a high voltage is used for power transmission. but itssurely not a good way to store engergy. (c) Automobiles are too small to possess device that can generate23000 V dc , and hence its not feasible to design such anautomobile. I hope this helps you
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