How are the moments about A (F_1) found? Rigid bar ABC supports a weight of W =

Question

How are the moments about A (F_1) found?

Rigid bar ABC supports a weight of W = 79 kN. Bar ABC is pinned at A and supported at B by rod (1), which has a circular cross section. If the normal stress in rod (1) must be limited to 240 MPa, determine the minimum diameter required for the rod (in mm). Sum moments about A to determine that the axial force in rod (1) is 118,500 N. Use the definition of normal stress to solve for the cross-sectional area of rod (1) required to satisfy the 240 MPa stress limit. Solve for the minimum rod diameter:

Explanation / Answer

Please Rate me first if my answer is correct with apt explanation : At A there are two components of forces ...Fxa and Fya At B there is only Fyb Balancing Forces in Horizontal direction we get ; Fxa = 0 N Balancing Forces in Vertical Direction we get ; Fya + Fyb = 79000 KN (at C) If we Moments about A M = Fyb x 2 - 79000x3 = 0 Fyb = 79000 x3/2 = 118500 N Fya = 79000-118500 = 39500 N Please Rate me first....

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