I am confused in part a as to why shearing stress in the pin is equal to 1/2C an

Question

I am confused in part a as to why shearing stress in the pin is equal to 1/2C and not just C. Could you explain this for me?

1.26 Knowing that a force P of magnitude 750 N is applied to the pedal shown, determine (a) the diameter of the pin at C for which the average shearing stress in the pin is 40 MPa, (b) the corresponding bearing stress in the pedal at C, (c) the corresponding bearing stress in the each support bracket at C. draw free body diagram of ACD since ACD is a 3-force member, the reaction at C is directed towards point E, the intersection of the lines of action of the other two forces.

Explanation / Answer

In part (a) its given that the AVERAGE shearing stress in the pin is 40 MPa and since it is symmetrical we use 1/2 C and not C

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.