A particle size of mass m is released from rest in the position shown and is acc

Question

A particle size of mass m is released from rest in the position shown and is accelerated to the left by the action of the elastic cord ABC which lies in the horizontal plane and which is upstretched at x=0. The cord has a stiffness k, which is the ratio of its tension force to its unit elongation or strain (Change in length divided by the original length). Determine the expression for velocity v reached by the particle at the initials x returns to zero. (Solve with out using work-energy principals)

PLEASE WORK THE PROBLEM "WITHOUT" ENERGY METHOD

Thanks.

Explanation / Answer

force by strain = 1/2kx = ma a = kx/2m v = kxt/2m

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