Question: Replace the force system acting on the frame by an equivalent resultan

Question

Question: Replace the force system acting on the frame by an equivalent resultant forcce and specify where the resultant's line of action intersects member BC measured from point B

***** I did most of the problem***

Fx = 35Cos60+25 = 42.5lb

Fy = 35Sin60+20 = 50.31lb

Theta=49.8 degrees

The solution for finding the moment here is:

Mra=Ma = 50.31(6)+42.5(d)=35Sin60(2)+20(6)-25(3)

d=4.62ft

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The only part of this problem that I'm confused by is where the distances on the moment are coming from. If someone could please explain why we are finding the Moment from A when the problem says from point B, that would be great. Any explanation as to what is going on in the moment calculations would be great, a quick 5star!!!

Explanation / Answer

the question asks about the the resultant's line of action intersects member BC measured from point B, and not the moment about B. and for our convenience we can use about point A you should try taking moment from B, and you will get the same answer

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