A closed-top tank is fitted with a valve on the side, as shown. The liquid in th

Question

A closed-top tank is fitted with a valve on the side, as shown. The liquid in the bottom of the tank and in the manometer is mercury, and top liquid is water at standard conditions. Dimensions are as provided. Compute the initial elevation and final of the mercury on the side pipe (measured from the bottom of the tank), before and after the maneuver of the upper valve, bringing the air pressure from -9 psi (gage) back to atmospheric pressure.

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Explanation / Answer

Initial: -6894.75729+(1000*9.81*0.3048)+(1.5*0.3048*5430*9.81) = (5430*9.81*(1.5+x)*0.3048) =>20,449.59747 = 16236.17784*(1.5+x) =>1.25951 = 1.5+x =>x = -0.2404 ft Final: 101300+(1000*9.81*0.3048)+(1.5*0.3048*5430*9.81) = (5430*9.81*(1.5+x)*0.3048) =>128644.3548 = 16236.17784*(1.5+x) =>7.92331521 = 1.5+x =>x = 6.4233152 ft

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