What is MFx, the contribution to the moment about point O made by the x componen

Question

What is MFx, the contribution to the moment about point O made by the x component of the force F at point A? What is MFy, the contribution to the moment about point O made by the y component of the force F at point A? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative.

Learning Goal: To apply the principle of moments and the principle of transmissibility

. As shown, a rope is attached to a l=13.0 ft high shed that is to be relocated. A man pulls on the end of the rope at point A; the rope is attached to the shed at point B. (Intro 1 figure) As the man pulls on the rope, it creates an angle theta with the horizontal. The end of the rope is located at x=15.0 ft from the shed and y=5.00 ft off the ground. The man pulls on the rope with a force of magnitude F=70.0 lb .

Express your answers numerically in pound-feet to three significant figures separated by commas.

MFx, MFy, M =............... lb*ft

Explanation / Answer

=arctan (l-y)/x = arctan ((13-5)/15) =0.489957326 rad

My = Fyx = F xsin = (70)*(15)*sin (0.489957326)= 494

Mx = Fxy = F ycos = (70)*5*cos (0.489957326)=309

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