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The magnitude of the vertical force vector W is 600 lb and the magnitude of the

ID: 1821124 • Letter: T

Question

The magnitude of the vertical force vector W is 600 lb and the magnitude of the force A is
1500 lb. If the system is in equilibrium, determine the force B and angle a. http://i54.tinypic.com/r201fm.jpg 1500 lb. If the system is in equilibrium, determine the force B and angle a. http://i54.tinypic.com/r201fm.jpg

Explanation / Answer

upward is +y towards right is +x let us say angle alpha is 'a'. balancing forces in y- direction -600 + Bsin50 - 1500sina = 0 .... 1 balancing forces in x-direction Bcos50 - 1500cosa = 0 =>B = 2333.6cosa substituting this value in 1 we get -600 + 2333.6cosa - 1500sina =0 let sina be k then cosa = sqrt(1-k2) so, 600 = 2333.6sqrt(1-k2) - 1500k =>k = 0.707 =>sina = 0.707 =>a = 45 B = 1650lb