Gasoline flows from the bigger tank to the smaller can. I believe this problem c

Question

Gasoline flows from the bigger tank to the smaller can.

I believe this problem can be solved using a simplebernoulli's equation... but I am confused.
The siphon is begun by sucking gasoline to fill the tube, thenone end is brought to a level lower than the tank, causing a flowof gasoline from the tank to the small can. The diagram Idrew is not to scale, but the flow travels up 2 meters from thetank, then goes down 2.75 meters into the can. Frictional losses in the tube are disregarded, this should bea somewhat simple fluid mechanics problem.
The diameter of the tube is 0.004 m The density of gasoline is 750 kg/m3 Gravity is 9.81 m/s2
So, I need to determine 1) the velocity of the gasoline at the point where it exitsinto the can. and 2) pressure at the highest point in the tube (2 meters abovethe original tank)
I'm not sure where to begin... Please help, thank you.


I believe this problem can be solved using a simplebernoulli's equation... but I am confused.
The siphon is begun by sucking gasoline to fill the tube, thenone end is brought to a level lower than the tank, causing a flowof gasoline from the tank to the small can. The diagram Idrew is not to scale, but the flow travels up 2 meters from thetank, then goes down 2.75 meters into the can. Frictional losses in the tube are disregarded, this should bea somewhat simple fluid mechanics problem.
The diameter of the tube is 0.004 m The density of gasoline is 750 kg/m3 Gravity is 9.81 m/s2
So, I need to determine 1) the velocity of the gasoline at the point where it exitsinto the can. and 2) pressure at the highest point in the tube (2 meters abovethe original tank)
I'm not sure where to begin... Please help, thank you.

Explanation / Answer

Set the tank as point 1, set the top of the tube as point 2,and set the outlet at the can as point 3. 1) To find velocity at the tube exit, use bernoullibetween points 1 & 3. Set your reference point at point3. You must reduce the equation using the followingconditions: a) Both points are at atmospheric pressure so they will cancelout. b) Point 3 is the reference point, so the elevation (z) willbe 0. c) The velocity of the tank level at point 1 is relatively 0compared with the fluid velocity at the exit of the tube. Using these conditions and solving for V3, yourequation reduces to: V3 = (2gz1) =(2)(9.81m/s2)(.75m) = 3.84 m/s 2) To find pressure at the high point, use bernoullibetween point 2 & 3. Leave your reference at point3. Use the following conditions to reduce the equation: a) The velocity in the tube at both points are equal(conservation of mass) so they will cancel out. b) Point 3 is still reference, so the elevation will still be0. c) The pressure at point 3 is at atmosphericpressure. Using these conditions and solving for P2, yourequation reduces to: P2 = Patm - gz2 =101.3kPa - (750kg/m3)(9.81m/s2)(2.75m)(1N /1kg*m/s2)(1kPa / 1000 N/m2) = 81.1 kPa NOTE: The last two parenthesis are to convert thegz2 to kPa Hope this helps... PLEASE RATE!!!!! NOTE: The last two parenthesis are to convert thegz2 to kPa Hope this helps... PLEASE RATE!!!!!

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