The winch cable on a tow truck is subjected to a force ofT=6kN when the cable is

Question

The winch cable on a tow truck is subjected to a force ofT=6kN when the cable is directed at = 600. Determine the magnitudes of the total break frictional force F forthe rear set of wheels B and the total normal forces at BOTH frontwheels A and both rear wheels B for equilibrium. The truckhas a total mass of 4 Mg and mass center at G. Answer: F=5.20 kN Na= 17.3kN Nb= 24.9kN The winch cable on a tow truck is subjected to a force ofT=6kN when the cable is directed at theta = 60 degree. Determine the magnitudes of the total break frictional force F forthe rear set of wheels B and the total normal forces at BOTH frontwheels A and both rear wheels B for equilibrium. The truckhas a total mass of 4 Mg and mass center at G. Answer: F=5.20 kN Na= 17.3kN Nb= 24.9kN

Explanation / Answer

For equilibrium in horizontal direction F = T *sin60 F = 6sin60 F = 5.196 or5.2kN For equilibrium in vertical direction Na + Nb = 4*9.8+6sin30 Na + Nb = 42.2-----------------------(1) and take moment about A =>4*9.8*2+6cos60*6+6sin60*3=Nb*4.5 Nb = 24.9 kN Na = 17.3 kN

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.