Find the power developed by the turbine, in Btu per lb fromthe following equatio

Question

Find the power developed by the turbine, in Btu per lb fromthe following equation: Work = mass flow rate(h1-h2) The units of work is supposed to be in Btu/lb. The unitsof mass flow rate are usually kg/s and the units of enthalphy canbe found in Btu/lb. How do I convert kg per second into Btuper lb? Find the power developed by the turbine, in Btu per lb fromthe following equation: Work = mass flow rate(h1-h2) The units of work is supposed to be in Btu/lb. The unitsof mass flow rate are usually kg/s and the units of enthalphy canbe found in Btu/lb. How do I convert kg per second into Btuper lb?

Explanation / Answer

hi, You should be able to understand the thermohomework problem you are asking about by following the steps
   below:    power = h1 - h2    at 300 lbf/in2 and800oF , h1 = 1421Btu/lb                             (from table)    at 5 lbf/in 2 , h2 =130.17 + 0.98 x 1000.9                            =1111.052 Btu/lb power = 1421 - 1111.052 = 309.948 Btu/lb.     "I hope this helps! Best of luck withthe rest of your coursework."    at 300 lbf/in2 and800oF , h1 = 1421Btu/lb                             (from table)    at 5 lbf/in 2 , h2 =130.17 + 0.98 x 1000.9                            =1111.052 Btu/lb power = 1421 - 1111.052 = 309.948 Btu/lb.     "I hope this helps! Best of luck withthe rest of your coursework."

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