A insulated piston-cylinder device contains 0.05 m 3 of saturated refigerant 134

Question

A insulated piston-cylinder device contains 0.05 m3of saturated refigerant 134a vapor at 0.8 MPa pressure. Therefrigerant is now allowed to expand in a reversible manner untilthe pressure drops to 0.4 MPa. Determine the final temperature inthe cylinder and the work done by the refrigerant. Please show all steps. A insulated piston-cylinder device contains 0.05 m3of saturated refigerant 134a vapor at 0.8 MPa pressure. Therefrigerant is now allowed to expand in a reversible manner untilthe pressure drops to 0.4 MPa. Determine the final temperature inthe cylinder and the work done by the refrigerant. Please show all steps.

Explanation / Answer

hi you should be able to understand thermodynamics homeworkproblem that you are asking about by the following stepsbelow: at 0.8MPa from R-134a tables v1=vg=0.0255m3/kg u 1=ug=243.78kJ/kg s1=sg=0.9066kJ/kg.K initial volume of the cylinderV1=0.05m3 mass of working fluid in he cylinder is m*v1=V1 m*0.0255=0.05 m=1.9607kg since the process is reversible adiabatic s1=s2 where s2=sf+x2sfg(at 0.4MPa)     0.9066=0.2399+x2*(0.9145-0.2399)     x2=0.9882 u2=uf+x2ufg    =61.69+0.9882*(231.97-61.69)    =229.96kJ/kg final temperature in the cylinder is saturation temperature at0.4MPa T2=8.930C work done=m(u1-u2)                 =1.9607(243.78-229.96)              W.D=27.096kJ I hope this helps best of luck with rest of your coursework I hope this helps best of luck with rest of your coursework     

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