From Question 2.2 on pg. 25: Two forces are applied to a bolt: 1) F1= 5kn at 25

Question

From Question 2.2 on pg. 25: Two forces are applied to a bolt: 1) F1= 5kn at 25 degrees CCWand 2) 8 kN CW a) Use the parallelogram law to find the resultant. ( I setit up where angle alpha equals 180 - (25 + 50) andthe resultant force equals F1^2 + F^2 -2(F1)(F2)cos(alpha) butI am getting a nonsensical answer) b) Use the triangle rule. (I used the sine rule but my ratiosfor each respective force are not equal) From Question 2.2 on pg. 25: Two forces are applied to a bolt: 1) F1= 5kn at 25 degrees CCWand 2) 8 kN CW a) Use the parallelogram law to find the resultant. ( I setit up where angle alpha equals 180 - (25 + 50) andthe resultant force equals F1^2 + F^2 -2(F1)(F2)cos(alpha) butI am getting a nonsensical answer) b) Use the triangle rule. (I used the sine rule but my ratiosfor each respective force are not equal)

Explanation / Answer

F1= 5 kN, = 25o, F2 = 8 kN, =50o. the resultant force R = [F12 + F22 -2F1*F2*cos(180 - - )] = 10.5 kN

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