A urn contains three blue and seven white chips. A chip is selected at random. I
ID: 1814620 • Letter: A
Question
A urn contains three blue and seven white chips. A chip is selected at random. If the color of the chip selected is white, it is eplaced and two more white chips are added to the urn. However, if the chip drwan is blue it is not replaced and no additional chips are put in the urn. A chip is then drawn from the urn a second time. What is the probability that it is white?
From the question above, suppose that we are given that the chip selected for the second time is white. What is the probability that the chip selected at the first stage is blue?
Explanation / Answer
(a) (1/2)(7/9) + (1/2)(9/12) = 7/18 + 3/8 = 55/72
(b) (7/18)/(55/72) = 28/55
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