a. There are 11 bits for page number in each logical address. b.There are 13 dis

Question

a. There are 11 bits for page number in each logical address.
b.There are 13 displacement bits in each physical address.

c. There are 11 displacement bits in each logical address.

d. The length of the logical address is 24 bits.

Consider a simple paging-based memory-management system in which each page table has 2K entries. Let each page table entry be 16 bits long, including a valid/invalid bit. The total physical memory in the system is 256MB.
How many frames are there in the physical memory? How many bits are needed to represent the displacement in each page/frame? What is the layout of the logical addresses (the total number of bits, the number of bits for the page number and the number of bits for displacement)? How many frames are there in the physical address space? What is the layout of the physical addresses?
Based on your answers to the questions above, identify the FALSE statement from among those below.

Explanation / Answer

c. There are 11 displacement bits in each logical address.

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