This is my first question! A digital filter difference equation is given by y(n)

Question:1 y(n)-y(n-1)=2x(n) =>Y(z){1-1/z} = X(z) {2} =>H(z) = Y(z)/X(z) = 2/(1-1/z) = 2z/(z-1)

ID: 1813430 • Letter: T

Question

This is my first question!

A digital filter difference equation is given by y(n)=y(n-1)+2x(n)
What is the filter transfer function?

This is my second question!

A digital filter transfer function is given by H(z)=1/(1-0.3z^-1-0.4z^-2)

Which of the following could be the filter impulse response? a and B are constants.

h(n)=a(0.3)^n+B(0.4)^n,= 0,1,2....

h(n)=a(-0.3)^n+B(-0.4)^n,= 0,1,2....

h(n)=a(0.5)^n+B(-0.8)^n,= 0,1,2....

h(n)=a(-0.5)^n+B(0.8)^n,= 0,1,2....

Third question is:

Fourth question is!!

A digital filter difference equation is given by y(n)=2x(n-1)-x(n-3)

What is the value of y(3) if the input is a unit step, that is x(n)=u(n)?

y(3)=1

=-1

Question:1

y(n)-y(n-1)=2x(n)

=>Y(z){1-1/z} = X(z) {2}

=>H(z) = Y(z)/X(z) = 2/(1-1/z) = 2z/(z-1)

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