Using Mesh Analysis, find V1, V2, I1, and I2 in the following DC circuit Using N
ID: 1812084 • Letter: U
Question
Using Mesh Analysis, find V1, V2, I1, and I2 in the following DC circuit Using Nodal Analysis, analyze the following circuit in the phasor domain (convert the inductor and capacitor into impedances and the source to its phasor equivalent) and find values for the phasors V1 rightarrow and I1 rightarrow. - 2 pts: For the circuit in Problem 1, What is the power delivered to the circuit by the voltage source? What is the power delivered to the circuit by the current source? How much power is absorbed by each of the resistors? Verify that the amount of power delivered is equal to the amount of power absorbed. Text book Problem 9.1 Text Book Problem 9.8 For each of the sinusoidal source (vg (t) ) functions shown, determine the complex exponential source(vgc (t) )_that has the given source as its real part. (Hint The real part must be a cosine) vg(t) = 5cos(6t) vg(t) = 5sin(6t) vg (t) = -10cos(2t + 60 degree ) vg(t) = 3sin(10t - 135 degree ) For each of the sinusoidal source functions shown in problem 5, determine the complex exponential source that has the given source as its imaginary part. (Hint: The imaginary part must be a sine) Text Book Problem 9.11 (remember to convert sines to cosines before creating the phasor)Explanation / Answer
let i1, i2, i3 are loop currents in clockwise direction
apply kvl for loop 1
20= 2i1+ 2(i1-i2)
4i1-2i2=20 ------------(1)
apply kvl for loop 2
4i2+ 2(i2-i3) + 2(i2-i1) =0
-2i1 +8i2 -2i3 =0 -------------(2)
apply kvl for loop 3
2(i3-i2) +2i3=0
-2i2 +4i3=0 ------(3)
from ckt i3=-1A
i3 substitute in eq3
i2=-4/2 =-2A
i2 substitute in eq1
i1=4A
I1=i1= 4A
I2= -i2 =2A
v1=2(i1-i2) =2(4+2) =12V
v2= 2(i2-i3) =2(-2+1) =-2V
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