Yes, I already answered these! But, I\'m not 100% confident in my work, so I\'d
ID: 18098 • Letter: Y
Question
Yes, I already answered these! But, I'm not 100% confident in my work, so I'd like to just check them to make sure they are correct and see, if I need to, what I did wrong and how to correct it before I submit my answers.
2. Using the pedigree chart below, determine the genotype of each individual, under the assumption that the trait is recessive. If you do not know one of the genes, replace it with a "?". Be parsimonious and assume that people who marry into the family do not carry the trait, unless that is clearly the case.
Explanation / Answer
Pedigree 1: Persons 1 and 2 are Aa (heterozygous) because both parents of a recessive child needs to have 1 recessive allele to donate. Person 3: A? Person 4: aa Person 5: Aa Person 6: Aa Person 7: A? Person 8: aa Question 10 - Yes, this is possible Pedigree 2: Person 1: aa Person 2: Aa Person 3: AA Person 4: AA Person 5: Aa Person 6: A? Person 7: A? Person 8: Aa Person 9: Aa Person 10: A? Person 11: aa Question 22 - yes Pedigree 3 Persons 1, 2, 3, 5, 6, and 7 do not display the trait and therefore must be homozygous recessive (aa). Persons 4 and 8 must be either heterozygous or homozygous dominant (A?). No, it is not possible for this trait to be dominant. The dominant trait cannot skip generations.
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