We also demonstrate a shortcut We designate one mesh within a supermesh as a pri

Question

We also demonstrate a shortcut We designate one mesh within a supermesh as a principal mesh and use KCL to write the other mesh other mesh currents in the supermesh as a sum of this principal-mesh current and current source values. We then write a KVL equation for the loop around the supermesh. This last step is similar to the analysis of a series circuit that does not have a current source. Write a set of mesh-current equations for the network shown in Fig. 4.12. With the network as drawn in Fig. 4.12, meshes 1 and 2. together with the shared current source and Ohm resistance, form one supermcsh. A KVL equation around the supermcsh is Which is the first mesh-current equation. The use of KCL permits us to write the 1 unrent source current in terms of mesh-current components:

Explanation / Answer

In the first Equation you dont have to multiply 0.769 with i1 and 12; I am completing the solution for you; In first loop -3+0.2i1 +(i1-i2) = 0; Second loop; (i2-i1) + 0.25 i2 -14 =0; Super mesh; -3+0.2i1+0.25i2-14=0; Now solve all 3 equations simultaneously.

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