Solving for n. we get = -2/3. Applying KVL around the outer loop to get VTh acro

Question

Solving for n. we get = -2/3. Applying KVL around the outer loop to get VTh across terminals a-b, we obtain -12 + 6i + 3i2 + 2(0) + VTh = 0 VTh = 22 V For maximum power transfer, RL = RTh = 9 Ohm and the maximum power is pmax = V2Th/4rL = 222/4 x 9 = 13.44 W Determine the value of RL that will draw the maximum power from the rest of the circuit in Fig. 4.52. Calculate the maximum power. Answer: 4.22 Ohm, 2.901 W. In this section, we learn how to use PSpice to verify the theorems cover in this chapter. Specifically, we will consider using dc sweep analysis find the Thevenin or Norton equivalent at any pair of nodes in a circle transfer to a load. The reader is advice to n

Explanation / Answer

SOLUTION: POWER P= 2.901W

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.