Enter question here... For the following parallel ac circuit Circuit 1, given: R
ID: 1804963 • Letter: E
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Enter question here...
For the following parallel ac circuit Circuit 1, given: R = 20 kilo-ohms XC = 5 kilo-ohms XL = 10 kilo-ohms is(t) = 2cos(1000t-90 degree)mA Match the following currents in polar form IR IL IC 360.2 micro-amperes angle(-82.6 degree) 1.3 milli-amperes angle(-243.4 degree) 631 micro-amperes angle(-63.4 degree) 753.6 micro-amperes angle(-172.6 degree) 456.7 micro-amperes angle(97.4 degree) 2.52 mili-amperes angle(26.6 degree) 904.5 micro-amperes angle(7.4 degree) 1.26 milli-amperes angle(-153.4 degree)Explanation / Answer
is(t) = 2Cos(1000t - 90) = 2Sin(1000t) mA
XC//XL = 50/15 = 10/3 kilo-ohms
R//XC = 100/25 = 4 kilo-ohms
R//XL = 200/30 = 20/3 kilo-ohms
corrent through R is
IR = 2Sin(1000t)*(XC//XL)/[R + XC//XL]
= (2/7)Sin(1000t) mA
corrent through Capacitor C is
IC = 2Sin(1000t)*(R//XL)/[XC + R//XL]
= (8/7)Sin(1000t) mA
corrent through Inductor L is
IL = 2Sin(1000t)*(R//XC)/[XL + R//XC]
= (4/7)Sin(1000t) mA
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