2.74 W c. 28.2 W d. 157 W A 200- resistor is electrical 15, a 10- sonnected in s
ID: 1796330 • Letter: 2
Question
2.74 W c. 28.2 W d. 157 W A 200- resistor is electrical 15, a 10- sonnected in series with a 10-pF capacitor and a 60-Hz, 120-V (rms) line voltage. If circuit connected for 24 hours? energy costs 5.0¢ 62¢ sot per kWh, how much does it cost to leave this b. 31e c. 5.2¢ d. 3.1 16. A conducting bar of length 20 cm constant angula netic field of rtts with a constant angular speed of 5 rad's about a pivot at the end. A plane of rotation. How much is the magnitude of the motional emf induced between the ends of the bar? a. 0.24 V b. 1.2 V e. 2.4 V d. 0.12 V tar 1o cm fWhat is largest possible value of the induced electric field outside the solenoid at a distance a· 6xx 10, V/m 17. A long solenoid of radius 5 cm has 100 turns per unit length. It carries a time-dependent current that varies as from its central axis? (Mo- 4x 10 T-m/A) × 10-5 V/m A long solenoid of radius 5 cm has 100 turns per unit length. It carries a time-dependent current that varies as 1o-10 cos(2 0) What is largest possible value of the induced electrie field inside the solenoid at a distance of d. 18. cm from its central axis? (0-4 × 10" Tm/A) a. 6× 10-6 V/m c. 2 × 10-6 V/m d. × 10-6 V/m 19. An ideal solenoid has 10 turns, is 8 cm long and has diameter of 2 cm. What is the amount of magnetic energ stored in its magnetic field when it carries a current of 20 A? a. 6x 103 J At t=0, an emfof 500 V is applied to a col that has an inductance L-4 H and a resistance R=100 Ohm. He much time should elapse for the energy stored in the inductor to reach the value 18 J? a. 0.0400s b. 0.0664s c. 0.0366 s d. 0.0864 s 20.Explanation / Answer
15)
impedance, Z^2=R^2 +Xc^2
Z^2=R^2 + 1/(w*c)^2
Z^2=200^2 + 1/(2pi*60*10*10^-6)^2
===> Z=331.21 ohm
now,
current, I=Vrms/Z
I=120/(331.21)
I=0.362 A
power, P=I^2*R
P=0.362^2*(200)
P=26.21 W
for 24 hr,
energy used, E=p*t
E=26.21*24
E=629.04 W*H
E=629.04*10^-3 KWH
total cost =629.04*10^-3*5
=3.1 cent --->is answer
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