21. 0.330.65 points | Previous Answers SerPSET9 36.P.077 My Notes The lens and m

Question

21. 0.330.65 points | Previous Answers SerPSET9 36.P.077 My Notes The lens and mirror in the figure below are separated by d = 1.00 m and have focal lengths of +94.7 cm and-53.4 cm, respectively. An object is placed = 1.00 m to the left of the lens as shown Object Lens Mirror 1.00 m 1.00 m (a) Locate the final image, formed by light that has gone through the lens twice. distance locationto the left of the lens cm (b) Determine the overall magnification of the image. (c) State whether the image is upright or inverted. upright O inverted Need Help? Read R

Explanation / Answer

a)

From thin lens equation

1/f1 =1/p1 +1/i1

1/0.947 =1/1 +1/i1

i1=1786.8 cm

object distance of mirror

p2=100-1786.8=-1686.8 cm

from thin lens formula

-1/53.4 =-1/1686.8 +1/i2

i2=-55.15 cm

Now object distance

q3=100+55.15=155.15 cm

from thin lens formula

1/94.7 =1/155.15 +1/i3

i3=243.07 cm (to the left of lens)

b)

Magnification

M=M1M2M3 =(-1786.8/100)(-55.45/1686.8)(-243.07/155.15)

M=-0.92

c)

since M<0 ,image is inverted

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