15) Two objects are thrown from the top of a tall building and experience no app
ID: 1795924 • Letter: 1
Question
15) Two objects are thrown from the top of a tall building and experience no appreciable air resistance. One is thrown straight up, and the other is thrown horizontally, both with the same initial speed. How do their speeds compare when they reach the street? A) The one thrown horizontally is traveling faster B) They will be traveling at the same sped. C) The one thrown up is traveling faster. 16) A spring-loaded dart gun is used to shoot a dart straight up into the air, and the dart reaches maximum height of 24 meters. The same dart is shot up a second time from the same gun, but this time the spring is compressed only half as far (compared to the first shot) How far up does the dart go this ime (neglect friction and assume the spring obeys Hooke's law)? A) 48 meters B) 12 meters C) six meters D) three meters 17) If a force always acts perpendicular to an object's direction of motion, that force cannot do work on the 17) object and therefore cannot change the ebject's speed or kinetic energy A) True B) False 18) Sue and Betti both ski down a hill, both starting from rest. Sue weighs more than Betts. Neglecting friction and wind resistance, which skier will have more kinetic energy at the bottom of the hill 18) A) Bett B) Sue C) They will have the same kinetic energy at the bottom of the hill 19) Two objects, one of mass m and the other of mass 2 m, are dropped from the top of a building Wher 19 they hit the ground A) the heavier one will have half the kinetic energy of the lighter one B) both will have the same kinetic energy C) the heavier one will have four times the kinetic energy of the lighter one D) the heavier one will have twice the kinetic energy of the lighter one E) the heavier one will have one-fourth the kinetic energy of the lighber one 20) A force-121-10, N acts on an object. How much work does this fore do astheobmt moves through a displacement 14^+ 11^ m? 3)78 B) 46 C) 278 D) None of the above E) 58JExplanation / Answer
The speed of the object thrown straight up will be higher
let they be thrown at v m/s
from height h
additional velocity in verticle direction due to height will be
dV = sqrt (2g h) =v'
for upward thrown object the final speed will be
Vf = v +v'
for horizontal one it will be
Vf' = sqrt (v^2 + v'^2)
Vf>Vf'
Please repost for other answers, thanks
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