River Pascal with a volume flow rate of 4.9x10^5 L/s joins with River Archimedes

Question

River Pascal with a volume flow rate of 4.9x10^5 L/s joins with River Archimedes, which carries 1.02x10^6 L/s to form the Bernoulli River. The Bernoulli River is 170 m wide and 20 m deep.
What is the speed of the water in the Bernoulli River? River Pascal with a volume flow rate of 4.9x10^5 L/s joins with River Archimedes, which carries 1.02x10^6 L/s to form the Bernoulli River. The Bernoulli River is 170 m wide and 20 m deep.
What is the speed of the water in the Bernoulli River?
What is the speed of the water in the Bernoulli River?

Explanation / Answer

Given,

Q(P) = 4.9 x 10^5 L/s ;

Q(A) = 1.02 x 10^6 L/s ; w = 170 m ; d = 20 m

The flow rate of Bernoulli river will be:

Q(B) = (4.9 x 10^5 + 1.02 x 10^6) = 1.51 x 10^6 L/s = 1.51 x 10^3 m^3/s

we know that,

Q = v A => v = Q/A

v = 1.51 x 10^3 m^3/s/(170 m x 20) = 0.444 m/s

Hence, v = 0.44 m/s

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