PRINTER VERSIONBACK NEXT ASSIGNMENT RESOURCES HW7_Ch27_Phys2FlChapter 27, Proble

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PRINTER VERSIONBACK NEXT ASSIGNMENT RESOURCES HW7_Ch27_Phys2FlChapter 27, Problem 099 2017-18 In the figure the ideal battery has emf's 36 V, the resistances are R1 = 29 k and R2 = 12 kQ, and the capacitor is uncharged, when the switch is closed at time t = 0, what is the current in (a) resistance 1 and (b) resistance 2? (c) A long time later, what is the current in resistance 2? 010 016 Chapter 2Z Problem 023 R2 033 092 (a) Number (b) Number (c) Number Units Units Units Review Score Review Results by Study Objective By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: O of 3 used SAVE FOR LATER SUBMIT ANSWERR

Explanation / Answer

given

e = 36 V

R1 = 29 kOhm = 29000 Ohm

R2 = 12 kOhm = 12000 Ohm

a )

using Ohm's Law

the current in resistor 1 is

i1 = V1 / R1

= 36 / 29000

i1 = 1.241 X 10-3 A

i1 = 1.241 mA

b )

the current through R2 is zero

so i2 = 0 A

c )

and the current through resistors is " I "

I = V / Req

I = 36 / 29000 + 12000

I = 8.78 X 10-4 A

I = 0.878 X 10-3 A

I = 0.878 mA

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