The average human has a density of 945 kg/m3 after inhalation, and 1020 kg/m3 af
ID: 1795608 • Letter: T
Question
The average human has a density of 945 kg/m3 after inhalation, and 1020 kg/m3 after exhalation. Fresh water has a density of 1000 kg/3, sea water a density of about 1025 kg/m3, and the Dead Sea (which is actually a lake), a density of about 1230 kg/3. Which of the following statements are true?
A human would float in fresh water after exhaling.
The human body will always float in the Dead Sea.
It is easier to swim in the Atlantic than in Lake Michigan.
Without making any swimming movements, what percentage of the human body would be above the surface in sea water after exhaling?
Explanation / Answer
Given
average density of human 945 kg/m^3 , at inhalation
1020 kg/m^3 , at exhalation
fresh water density 1000 kg/m^3
sea water density is 1025 kg/m^3
dead sea (lake) density is 1230 kg/m^3
A human would float in fresh water after exhaling, that is
ratio of densities are 1020/1000 = 1.02
if the buoyance force equal to the force of gravity then the body will floats
here it is not correct
The human body will always float in the Dead Sea
inhalation 945/1230 = 0.768 ==> 100-76.8 % =23.2 % of the body will be above the surface of water
exhalation 1020/1230 = 0.8292 ===> 100 - 82.92 % = 17.08 % of the body will be above the surface of the water
so the body will float
It is easier to swim in the Atlantic than in Lake Michigan, in correct ,
in Atlantic sea water density is less than the density of lake that is the buoyance force would be less than in lake
so It is difficult to swim in the Atlantic than in Lake Michigan.
in sea water density is 1025 kg/m^3
1020/1025 = 0.9951 ==> 100 - 99.51% = 0.49 % of the human body would be above the surface in sea water after exhaling
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