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e University-P 254-Fall17-CASH Activities and Due Dates HW 11:Oscillations /29/2

ID: 1795371 • Letter: E

Question

e University-P 254-Fall17-CASH Activities and Due Dates HW 11:Oscillations /29/2017 11:59 PM75/100 -Print Calculator .d Periodic Table on 8 of 10 Sapling Learning Map do A particle with mass 1.13 kg oscillates horizontally at the end of a horizontal amplitude of 0.977 m and a duration of 123 s for 65 cycles of oscillation. Find the frequency, f, the speed at the equilibrium position , the spring constant, k, the potential energy at an endpoint, u . the potential energy when the particle is located 60.9% of the amplitude away from the equilibrim position U, and the kinetic energy, K, and the speed, v, at the same position A student measures an Number Hz Number m/s Number N/m Number (Scroll down for more answer blanks) L) Prevous check Answer L) Next 91 Ext :

Explanation / Answer

1) f= 65/123=0.528 Hz

2) f = (1/2pi)*(k/m)

k= (0.528*2*pi)^2*m = 12.4 N/m

3) max potential energy

Umax = (1/2)*12.4*(0.977)^2 = 5.94 J

4) max speed

5.94 = (1/2)*1.13*Vmax^2

Vmax= 3.24 m/ s

5) U = (0.609)^2*5.94 = 2.2 J

6) K = 5.94-2.2= 3.74 J

7) 3.74 = (1/2)*1.13* v^2

v = 2.58 m/s