1. A loaded elevator with very worn cables has a total mass of 3000 kg, and the

Question

1. A loaded elevator with very worn cables has a total mass of 3000 kg, and the cables can withstand a maximum total tension of 40,000 N. (a) What is the maximum upward acceleration for the elevator if the cables are not to break? (b) what must the tension be in order for the elevator to move at a constant velocity? (e) What is the answer to part (a) if the elevator is taken to a planet where g 4.50 ms (d) What is the apparent weight of a 200 N object in the elevator when the elevator is accelerating upward at 3 mis passing over a frictionless pulley. The coefficient of kinetic friction between the block and the horizontal surface is 0.4. Find the acceleration of the blocks and the tension in the cord. 3. A book whose mass is 4 kg is projected up a long 40° incline with an initial speed of 25 m s The coefficient of kinetic friction between the book and the plane is 0. 20. (a) Find the magnitude of the friction force acting on the book as it moves up the plane. (b) For how much time does the book move up the plane.? (c) How far does the book move up the plane? (d) How much time does it take the book to slide from its position in part (c) back to its starting point? (e) With what speed does it arrive at this point? 4. Find the tension in each cord if the weight of the suspended object is 400 N. 5° 50° 300N The beam in the diagram weighs 80 N and is in complete equilibrium. Solve for Fa and Fb 5. Fa Fb 20N 50N 6. A car with a mass of 2000 kg moves around a circular track whose radius is 500m in 125 seconds. (a) What is the speed of the car? (b) What is the acceleration (c) What is the centripetal force acting on the car? (d) What is the coefficient of friction? e) What is the maximum speed that the car can have to remain on the circular track?

Explanation / Answer

(a)let the maximum accleration is a

40000-(3000*9.8)=3000a

We got a=3.53 m/s*s

(b)for constant velocity

T=mg=29400 N

(c)if g=4.5 m/s*s

We got a=8.83 m/s*s

(d)Apparent weight=200+(200*3)/9.8=261.2 N

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