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Edit View History Bookmarks People Window Help / Course Home (GOne tnd Of A Stretched Idea G Search Textbook Soutons ! ! (Gone End Of A Stretched idea x ×7 × Physics: Ch 11-SHM Secure https://session com/myct/itemView assignmentProblemiD 876104758offset next 11-SHM Problem 11.35-Enhanced- with Solution previous 9of 14 next Problem 11.35 Enhanced-with Solution Part A tthe distanoe of the glider from the fxed end of the spring varies between 1.83 m and 1.06 m, and the period of the oscilation is 2.15 ,Snd the force constant of the spring One end of a stretched ideal spring is atached to anartrack and tho other is attached to agkder wit, a mass of 0.340 kg.The glider is released and allowed to Express your answer with the appropriate units osoliate i n SHM You may want to review(LDag335-0 For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of StHM k, 1.1242-lm My Answers Give Up Incorrect: Try Again; 4 attempts remaining Part B Find the maximum speed of the glider Express your answer with the appropriate units Value Units 5 8

Explanation / Answer

a) w = 2 pi / T = 2 pi / 2.15 = 2.92 rad/s

w = sqrt (k/m)

force constant k = m w2 = 0.340 * 2.922

force constant = 2.9 N/m

b) vmax = A w

A = 1/2 (1.83 - 1.06) = 0.385 m

vmax = 0.385 * 2.92

speed = 1.12 m/s

c) amax = A w2

amax = 0.385 * 2.922

max acceleration = 3.28 m/s2

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