2.1 mol of monatomic gas A initially has 4900 J of thermal energy. It interacts
ID: 1794156 • Letter: 2
Question
2.1 mol of monatomic gas A initially has 4900 J of thermal energy. It interacts with 2.6 mol of monatomic gas B, which initially has 8200 J of thermal energy Part B What is the final thermal energy of the gas A? Express your answer to two significant figures and include the appropriate units. You may want to review ( pages 559-561) By-5700 J Submit My Answers Give Up ncorrect; Try Again; 4 attempts remaining Part C What is the final thermal energy of the gas B? Express your answer to two significant figures and include the appropriate units EValue Units Submit My Answers Give UpExplanation / Answer
total energy of the gases is E = 4900+8200 = 13100 J
final thermal energy of the gas A is Ef = nA*E/(nA+nB) = (2.1*13100)/(2.1+2.6) = 5853.2 J
final thermal energy of gas B is Ef = (nB*E)/(nA+nB) = (2.6*13100)/(2.1+2.6) = 7246.8 J
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