± Nuclear Power and Nuclear Weapons Part A Assume that an average city uses abou
ID: 1793885 • Letter: #
Question
± Nuclear Power and Nuclear Weapons Part A Assume that an average city uses about 8.5 1013 J of energy in a day A typical nuclear power plant converts 0.01% of the mass of its fuel into energy through nuclear reactions. How much fuel would be needed to power an average city for one day? Express the mass of fuel needed in kilograms to two significant figures. Hints mass = 9.4 kg Submit My Answers Give Up Correct Compare this to about 9.6 million kilograms of coal that would be needed to generate the same amount of energy. This calculation shows that the energy changes involved in nuclear reactions are on the order of one million times higher than those involved in chemical reactions, Significant Figures Feedback: Your answer 9.44 kg was either rounded differently or used a different number of significant figures than required for this part. Part B A fission-based nuclear bomb (such as those used in World War II) uses the same nuclear reactions and an amount of fuel similar to what you calculated in Part A. We wll assume for our approximate calculation that matter to energy conversion is at 0.01%, as in Part A. However, by allowing an uncontrolled chain reaction to occur, all of the bomb's energy can be released in about 1.0 × 10-0 s. avg Express your answer in watts to two significant figures. avg Submit My Answers Give UpExplanation / Answer
Energy = 8.5 x 10^13 J / year
Energy needed from nuclear power plant = (8.5 x 10^13) / (0.01/100)
= 8.5 x 10^17 J
E = m c^2
8.5 x 10^17 = m (3 x 10^8)^2
m = 9.44 kg
(B) E = 8.5 x 10^17 J
t = 1 x 10^-6 s
P = E/t = 8.5 x 10^23 W
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.