An electron has a de Broglie wavelength = 3.7×1010 m . h=6.626×1034Js, e=1.602×1

Question

An electron has a de Broglie wavelength = 3.7×1010 m . h=6.626×1034Js, e=1.602×1019C, me=9.109×1031kg. What is its momentum? Express your answer to two significant figures and include the appropriate units. p = 1.8×1024 kgms What is its speed? Express your answer to two significant figures and include the appropriate units. v = 2.0×106 ms What voltage was needed to accelerate it from rest to this speed? Express your answer to two significant figures and include the appropriate units. I did not know how to do the last part

Explanation / Answer

A)p=6.626*10^-34/3.7*10^-10

p=1.8*10^-24

B)p=mv

then,

v=p/m

=1.8*10^-24/9.109*10^-31

=2.0*10^6

C)E=v->v=E/q

E=p^2/2m

v=p^2/2mq

=(1.8*10^-24)^2/2*9.109*10^-31*1.6*10^-19

v=2.36.

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