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C a session.masteringphysics.com Item 4 Part A Determine the CM of an outstretch

ID: 1793099 • Letter: C

Question

C a session.masteringphysics.com Item 4 Part A Determine the CM of an outstretched arm using the table TABLE 7-1 Center of Mass of Parts of Typical Human Body, given as % 100 units) (full height and mass Distance of Hinge Hinge Points) Points from Floor (%) Center of Mass () 1%Height Above Flur) Percent Mass (Joints) 915% 6.9% 40.1% 6.6% 4.2% 1.7% 21.5% 91.2% 81.2% Base of skull on spine Shoulder joint dbow 62.2% Head Trunk and neck Upper arms Lower arms Hands 7 1.7% 553% 43.1% wrist 46.2% 521% Hip joint Knee joint Ankle joint Upper legs (thighs) 425% 285% 18.2% 9.6 Lower legs Feet 40% m Body at " 580% 100.0% For arm hanging verticaly Express your answer using three significant figures. 31.2 %, of the person's height along the line from the shoulder to the hand Submit My Answers Give Up

Explanation / Answer

From the given table of values, the height of the upper and lower and hands are

Xupper= 81.2-71.7= 9.5

Xlower= 81.2-55.3= 25.9

Xhand= 81.2-43.1= 38.1

Xcm= [(Xupper)(Mupper)+ (Mlower)(Xlower)+(Mhand)(Xhand)]/(Mupper+Mlower+Mhand)

Xcm=(6.6*9.5+4.2*25.9+1.7*38.1)/(6.6+4.2+1.7)= 18.9 %

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