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ent MESSAGE MY INSTRUCTOR ULL SCREEN PRINTER VERSION BACK NEXT A uniform ladder

ID: 1792921 • Letter: E

Question

ent MESSAGE MY INSTRUCTOR ULL SCREEN PRINTER VERSION BACK NEXT A uniform ladder is 14 m long and weighs 260 N. In the figure, the ladder leans against a vertical, frictionless wall at height h = 11 m above the ground. A horizontal force is applied to the ladder at distance d= 2.2 m from its base (measured along the ladder). If force magnitude F-58 N, what are (a), (b)y-components of the force of the ground on h t -tos tor what mininum vaiue of the force maomitude 7twvll the base of the adder fust bhrev start to move fow ard the waient of static fiction between the lader and the ground (a) Number (b) Number (c) Number (d) Number (e) Number Units N Units N Units N Units This answer has no units olic 2000-2017 John Wley &Sons;, Inc. All Rights Reserved. A Division of John Wiley & Sons Inc Version 4.24.2

Explanation / Answer

given l = 14 m

W = 260 N

h = 11 m

horizontal force = F = 58 N

d = 2.2 m

a. let the reaction forces of the floor be Rx, Ry and that of the wall be Nx

then from force balance

F = Rx + Nx

W = Ry

from torque balance about the bottom contact point

F*d*h/l + W*(l/2)*sqroot(l^2 - h^2)/l = Nx*h

58*2.2*11/14 + 260*7*sqroot(196 - 121)/14 = Nx*11

Nx = 111.462 N

Rx = -53.4627 N

Ry = 260 N

b. Ry = 260 N

if F = 140 N

c. 140*2.2*11/14 + 260*7*sqroot(196 - 121)/14 = Nx*11

Nx = 124.3483 N

Rx = 15.6515 N

d. Ry = 260 N