C Seaure https//www byshudent/Pessignemem-Rarsponses/last?dep-17045323 OSColPhys

Question

C Seaure https//www byshudent/Pessignemem-Rarsponses/last?dep-17045323 OSColPhys2016 8.5 WA 045 y Notes O Ask Your A hockey player with a mass of 46.0 kg is traveling due east with a speed of 3.35 m/s. A second hockey player with a mass of 74.5 kg is moving due south with a speed of 6.80 m/s. They collide and hold on to each other after the collision, managing to mave off at an angle 0 south of east, with a speed of vr. Assume friction may be ignored and determine the following (a) the angle 7319 south of east (b) the speed v From part (a), you should have found the components of the final velocity. How can you use thern to find the magnitude of the velocity, or speed? m/s Additional Materials Reading 10. My Notes Ask Your Teacher

Explanation / Answer

Momentum Conservation along south:

Initial = 6.8 x 74.5 = 506.6

Final component of velocity along south =  506.6 / (46+74.5) = 4.20 m/sec

Momentum Conservation along east:

Initial = 3.35 x 46 = 154.1

Final component of velocity along east =  154.1 / (46+74.5) = 1.28 m/sec

Net velocity = sqrt(4.2^2 + 1.28^2) = 4.39 m/sec

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.