Problem 2: Inclined to Stay (25 points) A box of mass m 35 kg is placed on an in
ID: 1792535 • Letter: P
Question
Problem 2: Inclined to Stay (25 points) A box of mass m 35 kg is placed on an incline that makes an an horizontal. angle of 20° with the Static friction causes the box to remain stationary on the incline. 35 kg 20° 2.1: (5 points) Draw a free-body diagram for the box, labeling all forces acting on the box and showing their directions. 2.2: (10 points) Find the magnitude of the static friction force acting on the box. 2.3: (10 points) Find the minimum coefficient of static friction, " between the box and the incline.
Explanation / Answer
2.2)perpendicular to incline
N=mg cos 20
Parallel to inlcine
fs=mg sin 20=35*9.8*sin20=117.3 N
2.3)we know
fs =mu* N
mu=coeficient of static friction=fs /mg cos 20 =mgsin20/mgcos20=tan20=0.36
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