iPad 9:16 PM webassign.net 1. 3.76/5 points | Previous Answers SerPSET9 29 P.014
ID: 1792242 • Letter: I
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iPad 9:16 PM webassign.net 1. 3.76/5 points | Previous Answers SerPSET9 29 P.014 My Notes Ask Your Teacher An accelerating voltage of 2.28 x 103 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 37.8 cm away (a) What is the magnitude of the deflection on the screen caused by the Earth's gravitational field? 1.75e-16 X Your response differs from the correct answer by more than 10%. Double check your calculations, m (b) What is the direction of the deflection on the screen caused by the Earth's gravitational field? O up O down east west (c) What is the magnitude of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0 T down? (d) What is the direction of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0 HT down? north O south east westExplanation / Answer
speed of beam after accelerating through given voltage,
m v^2 /2 = q V
(9.109 x 10^-31)(v^2/2) = (1.602 x 10^-19)(2.28 x 10^3)
v = 2.83 x 10^7 m/s j
due to gravity. a = 9.81 m/s^2 downwrads
t= d / v = 1.335 x 10^-8 sec
deflection = a t^2 /2 = 8.74 x 10^-16 m
(c) q v B = m v^2 / r
r = m v / q B = 8.06 m
r sin(theta) = 0.378
theta = 2.7 deg
deflection = r (1 - cos(theta)) = 8.9 x 10^-3 m
= 8.9 mm
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