i need the final answer plz Chapter 26, Problem 034 Your answer is partially cor

Question

i need the final answer plz

Chapter 26, Problem 034 Your answer is partially correct. Try again. The figure shows wire section 1 of diameter D1-5.00R and wire section 2 of diameter D2-4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.10 m shown in section 2 is 7.00 . The number of charge carriers per unit volume is 8.00 x 1028 m 3 What is the drift speed of the conduction eectons n section 1? Di D2 Number8.079E-9 Units m/s the tolerance is +/-290

Explanation / Answer

n = 8.00 * 1028 m-3

electric field = 7.00 muV / 2.10 = 3.33 muN/m

J2 = 3.33 * 10-6 / 1.69 * 10-8 = 197 A/m2

J1 (4 pi R2) = J2 ( pi R2)

J1 = J2 / 4 = 49.25 A/m2

vd = J1 / n e = (49.25) / (8.00 * 1028 * 1.6 * 10-19)

drift speed = 3.85 * 10-9 m/s

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.