The potential in a region between x = 0 and x = 6.00 m is V= a + bx, where a = 1

Question

The potential in a region between x = 0 and x = 6.00 m is V= a + bx, where a = 19.0 V and b =-5.90 V/m. (a) Determine the potential at x = 0. Determine the potential at x = 3.00 m. Determine the potential at x = 6.00 m. (b) Determine the magnitude and direction of the electric field at x - 0 magnitude direction -Selecti V/m Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude direction Select V/m Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude directionSelect. i V/m

Explanation / Answer

a)

V = 19 - 5.90 x

at x = 0

V = 19 - 5.90 (0)

V = 19 Volts

at x = 3

V = 19 - 5.90 (3)

V = 1.3 Volts

at x = 6

V = 19 - 5.90 (6)

V = - 16.4 Volts

b)

electric field is given as

E = - dV/dx = - b

magnitude = - (-5.90) = 5.90

direction : +Ve X-axis

at x = 3

electric field is given as

E = - dV/dx = - b

magnitude = - (-5.90) = 5.90

direction : +Ve X-axis

electric field is given as

E = - dV/dx = - b

magnitude = - (-5.90) = 5.90

direction : +Ve X-axis

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