webassign.net Inbox 56@gmail.com-Gmail HW#14/15-Transformers, Inductor circuit C
ID: 1791684 • Letter: W
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webassign.net Inbox 56@gmail.com-Gmail HW#14/15-Transformers, Inductor circuit Course: EC 202 (001) Fall 2017 Principles of Ma k 2 7. -3 points GianPSE4 30.P034. My Notes A 720 pF capacitor is charged to 130 V and then quickly connected to a 180 mH inductor. (a) Determine the frequency of oscillation. kHz (b) Determine the peak value of the current. MA (c) Determine the maximum energy stored in the magnetic field of the inductor 8. -12 points GianPSE4 30.P.035. My Notes At t = 0, Qo = 5 C and I = 0 in an LC circuit. (a) At the first moment when the energy is shared equally by the inductor and the capacitor, what is the charge on the capacitor? (b) How much time has elapsed (in terms of the period )? 9. -1 points GianPSEWA4 30.P.017 My Notes The circuit below shows a simple RL circuit.Explanation / Answer
7)
C=720pF =720*10-12F
L=180mH =180*10-3H
a)fo =1/2(LC) =1/2(720*10-12*180*10-3) =13980.33 Hz or 13.98 KHz
b)Q =CV
the peak value of the current is
Io = Qw = CV = 720*10-12*130*2*13980.33 =8.22*10-3A or 8.22mA
c)The maximum energy stored in the inductor is
U =(1/2)LIo2 =(1/2)*180*10-3(8.22*10-3)2 = 6.083*10-6 J
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8)
a) total energy E = Qo2/(2C)
when the energy is shared equally by theinductor and the capacitor, then the energy on the capacitor ishalf of E, so q2/(2C) = (1/2)Qo2/(2C)
q = Qo/2 = 5/2 C = 3.54 C
b) q(t) = Qocos(2t/T)
when q = Qo/2, cos(2t/T) = 1/2
2t/T = /4
t = T/8 = 0.125 T
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