5 Problem 2 : Three beads placed on the vertices of an equilateral triangle of (

Question

5 Problem 2 : Three beads placed on the vertices of an equilateral triangle of (%) side 3.9 The first bead of mass m1-135 g is placed on the top vertex. The second bead of mass m2 = 45 g is placed on the left vertex. The third bead ofmass ms = 95 g is placed on the right vertex. are 72 Otheexpertta 25% Part(a) write a symbolic equation for the horizontal component of the center of mass relative to the left vertex of the triangle Grade Summa Deductions Submissions Attempts remain (4% per attempt detailed view In m1 Submit Hint I give up deduction per feedback Hints: tu deduction per hint. Hints remaining: 2 ii 25% Part (d) Feedback: 0 25% Part (b) Find the horizontal component of the center of mass relative to the left vertex, in centimeters. 25% Part (c) write a symbolic equation for the vertical component of the center of mass relative to the base of the triangle. Find the vertical component of the center of mass relative to the base of the triangle, in centimeters.

Explanation / Answer

m1 = 135 g

(x1 , y1) = (d/2 , d*sin60 ) = ( d/2 , d*0.866) = (1.95 , 3.38)

m2 = 45 g

(x2 , y2) = (0 , 0)

m3 = 95 g

(x3 , y3) = (d , 0) = (3.9 , 0)

part (a)

Xcm = ( (m1*x1) + (m2*x2) + (m3*x3) )/(m1+m2+m3)

Xcm = ( (m1*d/2) + (m3*d))/(m1+m2+m4)

===================================

part (b)

Xcm = ( (135*1.95) + (45*0) + (95*3.9) )/(135 + 45 + 95)

Xcm = 2.3 cm

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part (c)

Ycm = ( (m1*y1) + (m2*y2) + (m3*y3) )/(m1+m2+m3)

Ycm = ( (m1*0.866d) )/(m1+m2+m3)

===================================

part (d)

Ycm = ( (135*0.866*3.9) + (45*0) + (95*0) )/(135 + 45 + 95 )

Ycm = 1.66 cm

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