(5%) Problem 4:Suppose a double-slit interference pattern has its third minimum
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Question
(5%) Problem 4:Suppose a double-slit interference pattern has its third minimum at an angle of 029 with slits that are separated by 323 m. Randomized Variables = 0.2970 d = 323 m Calculate the wavelength of the light in nm. Grade Summary Deductions 09. Potential 100% sinO tan() Submissions Attempts remaining: 7 (096 per attempt) detailed view cotanasin acos0 4 5 6 atan0 acotan sinh0 coshO tanh0 cotanhO Degrees Radians CLEAR Submit Hint I give up! Hints: 296 deduction per hint. Hints remaining: Feedback: 20% deduction per feedback.Explanation / Answer
4. double slit has 3rd minimum at theta = 0.297 deg
a = slit seperation = 323 micro m
a. wavelength of light = lambda
now,
sin(theta) = (2n - 1)*lambda/2a
sin(0.297) = 5*lambda/2*323*10^-6
lambda = 669.721 nm
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