Please answer all four questions. These questions are from a physics II lab call

ID: 1791614 • Letter: P

Question

Please answer all four questions. These questions are from a physics II lab called "Uncovering a Hidden RCL Series Circuit" and I believe they can be answered without seeing the entire lab. Thank you in advance!

1) Why is it L/R not LR for the charging and discharging a series RL circuit? 2) In determination of capacitance (C) in an RC circuit in part II, the voltage probe is connected across the capacitor. What will you observe if the voltage probe is connected across RD (RD-resistor of decade box) instead? Can you determine capacitance from this? 3) In the determination of inductance (L) in an RL circuit in Part III, the voltage probe is connected across Rp. What will you observe if the voltage probe is connected across the terminals of the inductor instead? Can vou determine inductance from this? 4) If a sinusoidal signal is used instead of square wave in the function generator, what kind of graphs do you expect in the RC and RL circuit?

Explanation / Answer

1. for a series LR circuit

voltage drop across Resistanve = iR

voltage drop across inductor = Ldi/dt

so V = iR + Ldi/dt

V = i + (L/R)di/dt

as cvoefficient of di/dt comes to be L/R, and when solving this equation L/R remains as it is in charging or discharging equations

hence it is L/R and not LR in discharge / charginng of inductor

2. in deptermination of capacitor, volemter is connected across capacitor and Vc is measured. If voltmeter was connected agaionst the resistor, we will be measuing V - Vc = Vr and from hwere we can calculate the capacitance

3. in RL circuit, the voltmeter is connected axross Resistor to measure V - Vl = Vr. If we copnnected it across inductor wee can measure Vl = V - Vr and find inductance form there

4. in sinusoidal input is used instead of a square wave , then everytime the voltage of the sniusoidal gr4aph rises above the voltgage in the circuit, it will start charging the circuit and otherwise it will discharge. this will basically smoothen out the input sinusoidal graph into a sawtooth shape.

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Please answer all four questions. These questions are from a physics II lab call

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