1. 13.75/15 points | Previous Answers My Note Use the exact values you enter to

Question

1. 13.75/15 points | Previous Answers My Note Use the exact values you enter to make later calculations. A group of students performed the same "Conservation of Mechanical Energy" experiment that you performed in lab. However, instead of keeping the horizontal portion of the ramp at a constant height h2 from the tabletop, they varied this height and released the ball from the same height hec time. They then entered their results into the first two columns of the table shown in part (a). (a) Complete the table belovw Height of ramp from Horizontal distance d (cm) 36.45 51.70 58.85 67.94 74.95 V2kin (cm/s) 236.5 239.3 238.1 233.4 236.3 Trial #1 table top h2 (cm) 11.65 22.90 29.97 41.55 49.34 (b) Use the average value of v2kin to determine the height h1 through which the ball falls. 28.6 cm Additional Materials Conservation of Mechanical Energy

Explanation / Answer

Average velocity = (236.5+239.3+238.1+233.4+236.3)/5 = 236.72 cm/s

Average kinetic energy at height h2 = 0.5*m*Vavg2

K.Eavg = m*28018.18 kg.cm2s-2

h2,avg = (11.65+22.90+29.97+41.55+49.34)/5 = 31.08 cm

Applying work energy theorem

m*g*h1 = mg*h2,avg + K.Eavg

h1 = 31.08 + 28018.18/981 because-------- g = 981 cm/s2

h1 = 59.64 cm

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