6.)After a 0.325-kg rubber ball is dropped from a height of 18.5 m, it bounces o
ID: 1791158 • Letter: 6
Question
6.)After a 0.325-kg rubber ball is dropped from a height of 18.5 m, it bounces off a concrete floor and rebounds to a height of 15.0 m.
(a) Determine the magnitude and direction of the impulse delivered to the ball by the floor.
(b) Estimate the time the ball is in contact with the floor to be 0.03 seconds. Calculate the average force the floor exerts on the ball.
8.)A neutron in a nuclear reactor makes an elastic, head-on collision with the nucleus of a carbon atom initially at rest.
magnitude kg · m/s direction ---Select--- right left up downExplanation / Answer
6. (A) v0 = sqrt(2 x 9.81 x 18.5) = 19.05 m/s downward
vf = sqrt(2 x 9.81 x 15) = 17.16 m/s upward
Impulse =change in momentum
= 0.325 ( 17.16 + 19.05)
= 11.77 kg m/s
direction -> upward
(B) Impulse = F t
F = (11.77)/0.03 = 392.2 N up
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