Practice Problem 8.1 The total momentum P is a vector quantity with these compon

Question

Practice Problem 8.1 The total momentum P is a vector quantity with these components. Its magnitude is P2.0x10* kg-m/s)+ (1.5 x 10* kg-m/s) Let's begin by calculating the total momentum of two moving objects. Suppose a small compact car with a mass of 1000 kg is traveling north on at a speed of 15 m/s. At the intersection of Morewood and Fifth Avenues, it collides with a truck with a mass of 2000 kg that is traveling east on Fifth Avenue at 10 m/s. Treating each vehicle as a particle, find the total momentum (magnitude and direction) just before the collision. = 2.5 × 104 kg·m/s Morewood Avenue Its direction is given by the angle in (Figure 2), where Py Pc = 36.90 1.5×104 kg·m/s 2.0 × 104 kg-m/s 3 REFLECT It is essential to treat momentum as a vector. When we add the momenta of the two objects, we must do vector addition using the method of components. Each vehicle has momentum in only one coordinate direction and so has only one nonzero component of momentum, but the total momentum of the system has both x and y components. Part A Practice Problem: If the car is moving at 19 m/s, how fast must the truck move for the total momentum vector to make a 60°angle with the z axis (and 30 with the +y axis)? Express the velocity to two significant figures and include the appropriate units. I Figure 1 of 2 y Cnorth 5.3 x (east) m 2000 k = 15 Submit My Answers Give Up Incorrect; Try Again; 12 attempts remaining; no points deducted mA 1000 kg Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures

Explanation / Answer

Momentum of car Py = 1.9x104 kg m/sec
Momentum of truck Px = 2000 V where V is speed of truck.

If theta is angle made by total omentum with x-axis,
tan(theta) = Py/Px
for theta = 60 deg
tan 60 = 2000V / 1.9x104
V = 16 m/s

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